Bengals DE Carlos Dunlap Named AFC Defensive Player of the Week

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Cincinnati Bengals defensive end Carlos Dunlap greets fans before an NFL football game against the Cleveland Browns, Sunday, Dec. 29, 2019, in Cincinnati. (AP Photo/Bryan Woolston)

Bengals DE Carlos Dunlap today was named AFC Defensive Player of the Week for Week 17 for his performance in the team's win vs. the Cleveland Browns.

Dunlap recorded 2.5 sacks on Sunday, and added a forced fumble, a pass defensed and an additional QB hit. Dunlap was also a key component to the Bengals' defense holding Browns RB Nick Chubb, the NFL's second-leading rusher entering Sunday's game (5.0 yards per carry, 99.6 yards per game), to just a 3.2-yard average and 41 total rushing yards.

Dunlap played in 13 games (all starts) this season, and had 63 tackles, a team-high nine sacks, eight passes defensed and two forced fumbles. He now stands at 81.5 sacks for his career, just two shy of DE Eddie Edwards (83.5) for the Bengals' all-time lead.

This is Dunlap's fifth career AFC Player of the Week award, and his second of 2019. He earned the defensive award in Week 13 this season for his performance vs. the N.Y. Jets. His previous defensive award wins came in Week 8 of 2017 and Week 13 of '12, and he won the special teams award in Week 15 of '15.

Dunlap is one of just three current Bengals who have won multiple POW awards (QB Andy Dalton also has three, and DT Geno Atkins has two).